fastest way to multiply any number by 9-Program

Give a fastest way to multiply any number by 9.

Answer:

#include <stdio.h>

#include <conio.h>

void main()

{

int n;

printf(“Enter a number:”);

scanf(“%d”,&n);

printf(“%d”, (n<<3)+n);

getch();

}

Add two numbers without operator

Add two numbers without using operators...
clue:
printf("%*d",5,4);
the return type of printf is int..in this the number 5 will be assigned to the * and the number 4 will be assigned to the d.
so the output will be
output:
     4
i.e.., 5 spaces then 4 will be printed

Reverse coding

Hi friends...

lets crack some codes..

Following are some sample inputs and outputs.Find the logic and make the code

sample:

try it yourself

here is the answer:

#include<iostream.h>

#include<conio.h>

#include<math.h>

void main()

{

start:

long int input,i;

long  mul=1;

long double result;

cout<<"\nEnter a positive number:";

cin>>input;

for(i=1;i<=input;i++)

{

mul=mul*input;

}

result=2.303*log10(mul);

cout<<result;

goto start;

}